sum of series of following equation
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Arvind Sharma
on 14 Oct 2020
Commented: Ameer Hamza
on 14 Oct 2020
lamda=0.3:0.01:1.4; % unit micro-meter
Ec2=(1.24./lamda);
alpho=2e4;
alpha= real(alpho.*(sqrt(Ec2-1.51)));
d=1e-4;
JPh2=exp(-1.*alpha.*d); % equation 1
lamda1=0.82;
% now the summation of eqaution 1 goes from 0 to lamda1,
so how to calculate this sum of series
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Accepted Answer
Ameer Hamza
on 14 Oct 2020
You can use logical indexing to isolate the required values and then use sum()
lamda=0.3:0.01:1.4; % unit micro-meter
Ec2=(1.24./lamda);
alpho=2e4;
alpha= real(alpho.*(sqrt(Ec2-1.51)));
d=1e-4;
JPh2=exp(-1.*alpha.*d); % equation 1
lamda1=0.82;
idx = lamda < lamda1;
out_value = sum(JPh2(idx));
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