# Array value replace when change in row

3 views (last 30 days)
Vivek Shukla on 17 Oct 2020
Commented: Vivek Shukla on 19 Oct 2020
I have one row of matrix
A = [ 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 1 ; 1 ; 1 ; 1 ; 1 ; 1 ; 1 ; 1 ; 1 ; 1 ; 1 ]
the row has only two value 0 and 1. I want the code that will check the row if vaule change in row it will leave the first value change and aftre that it puts 0.
Output ::
A = [ 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 1 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ; 0 ]
Here you can see value of row is change at (13,1) position so it leave the first 1 and remaing 1 is replaced by 0.
Note::: this is example actual row size is 1508 x 1.

Matt J on 18 Oct 2020
Edited: Matt J on 18 Oct 2020
A=randi([0,1],7,10); %Example
[m,n]=size(A);
[~,idx]=max(A,[],1);
out = sparse(idx,1:n,1,m,n) ;
A,
A = 7×10
1 0 0 1 1 0 0 0 0 0 0 1 1 0 1 0 1 0 1 1 1 1 1 0 1 0 1 1 0 1 0 0 1 1 0 0 0 0 1 1 1 1 1 1 0 1 0 0 1 0 0 0 1 1 1 0 1 1 0 0 1 1 1 0 0 1 1 0 1 1
full(out)
ans = 7×10
1 0 0 1 1 0 0 0 0 0 0 1 1 0 0 0 1 0 1 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Vivek Shukla on 19 Oct 2020
yes sir I tried but its not working run the command sir you will get all idea thanks
Vivek Shukla on 19 Oct 2020
I got my answer thanks for you help.......

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