How to convert 16 X 2 char into a String?

I have a 16x2 char. the values are:

69
C4
E0
D8
6A
7B
04
30
D8
CD
B7
80
70
B4
C5
5A

I want it as 69C4E0D86A7B0430D8CDB78070B4C55A

what should be the code plz help.

[EDITED, Jan, string fomatted]

[Kushal Khaitan]

I want it as '69C4E0D86A7B0430D8CDB78070B4C55A'

[Kushal Khaitan]

This is the input : '69' 'C4' 'E0' 'D8' '6A' '7B' '04' '30' 'D8' 'CD' 'B7' '80' '70' 'B4' 'C5' '5A'

[Jan]

@Kushal Khaitan: Do you see that we are wildly guessing what your input could be exactly? This wastes your and our time. It is more efficient, if you post the format of your input data in a valid Matlab syntax. The type and class of your input is still not well defined. Is it a cell string? Then this would have cleared this immediately:

data = {'69' 'C4' 'E0' 'D8' '6A' '7B' '04' '30' 'D8' 'CD' 'B7' '80' '70' 'B4' 'C5' '5A'}

Answer 1

[Azzi Abdelmalek]

x='69 C4 E0 D8 6A 7B 04 30 D8 CD B7 80 70 B4 C5 5A';
x(regexp(x,' '))=[]

[Kushal Khaitan]

This is not working

[Jan]

Before the formatting, the question looked like:

 69 C4 E0 D8 6A 7B 04 30 D8 CD B7 80 70 B4 C5 5A

and the REGEXP approach would be reasonable. But then this would be more efficient:

x(x==' ') = [];

However, after the formatting it gets clear, why the title claims the data have the size 16 x 2.

As I've said before: The formatting in this forum is not intuitive, although it is a very important feature.

Answer 2

[Azzi Abdelmalek]

Ok, I did not read your edit, try this

x='69 C4 E0 D8 6A 7B 04 30 D8 CD B7 80 70 B4 C5 5A';
x=regexp(x,' ','split')

[Azzi Abdelmalek]

I think I've not understood, the reverse is

y=char(x)';
out=y(:)'

Answer 3

[Walter Roberson]

x = {'69' 'C4' 'E0' 'D8' '6A' '7B' '04' '30' 'D8' 'CD' 'B7' '80' '70' 'B4' 'C5' '5A'};
y = horzcat(x{:});

Answer 4

[Jan]

Without a proper formatting, the structure of your input is not clear. Did you recognize this?

x = ['69'; ...
     'C4'; ...
     'E0'; ...
     'D8'; ...
     '6A'; ...
     '7B'; ...
     '04'; ...
     '30'; ...
     'D8'; ...
     'CD'; ...
     'B7'; ...
     '80'; ...
     '70'; ...
     'B4'; ...
     'C5'; ...
     '5A'];
s = reshape(transpose(x), 1, []);