How to convert a vector of integers to a vector of characters?

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Hi - I have a vector of ints, typically 0/1, like this:
[0 0 0 0 1 0 0 0 0 1]
and I want to get this:
['0' '0' '0' '0' '1' '0' '0' '0' '0' '1']
But I cannot figure it out for the life of me. I'm sure it's simple. Thanks for your time and help.

Accepted Answer

James Tursa
James Tursa on 10 Feb 2013
Another method for single digits:
A = [0 0 0 0 1 0 0 0 0 1];
B = char(A+'0');

More Answers (3)

Wayne King
Wayne King on 9 Feb 2013
Edited: Wayne King on 9 Feb 2013
A = [0 0 0 0 1 0 0 0 0 1];
B = num2str(A);
Now B is a vector of characters
  2 Comments
Michael
Michael on 9 Feb 2013
Hi Wayne -- I knew of num2str and tried that, but it turns out you're right. But what I figured out was that it was the extra spaces in the result of num2str that was throwing me off. i.e. num2str([0 0 0 0 0]) = '0 0 0 0 0', which is length 9 or something (but not 5). I removed the spaces from the result of num2str and it worked great. Thanks for the help.

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Azzi Abdelmalek
Azzi Abdelmalek on 9 Feb 2013
Edited: Azzi Abdelmalek on 9 Feb 2013
a = [0 0 0 0 1 0 0 0 0 1];
y=arrayfun(@(x) cellstr(num2str(x)),a)
% To get any character
y{4} % for e.g

Jan
Jan on 10 Feb 2013
Edited: Jan on 10 Feb 2013
Instead of removing the spaces from the output of num2str, you can create string without spaces directly:
a = [0 0 0 0 1 0 0 0 0 1];
s = sprintf('%d', a);
Another fast but more strange method is:
s = char('0' + a);

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