4byte uint8 array to single uint32 value
67 views (last 30 days)
Show older comments
Maximilian Becker
on 7 Dec 2020
Commented: Steven Lord
on 25 May 2023
I have an uint8 array containing 4 elements each representing 1byte.
myArray = [0x32 0x45 0x56 0x81] % just an example
% looks like this: myArray(1)=8bit, myArray(2)=8bit, myArray(3)=8bit, myArray(4)=8bit]
I mainly need to extract all the 32 bits and combine them to one uint32 value:
myValue = 0x32455681
%should look like this 32bit: myArray(1)myArray(2)myArray(3)myArray(4)
The goal is basically to remove the array structure and chain all the 32bits together
I once came from such an uint32 number and used the rearrange and bitget function to crate this array structure, but I somehow don't see how to come back.
As an important requirement, all the used functions must be able to be generate to C code
Any ideas?
0 Comments
Accepted Answer
Ameer Hamza
on 7 Dec 2020
Edited: Ameer Hamza
on 7 Dec 2020
You can use typecast()
myArray = [0x32 0x45 0x56 0x81];
out = swapbytes(typecast(myArray, 'uint32')); % swapbytes is needed on little-endian systems
Result
>> out
out =
uint32
843404929
>> dec2hex(out)
ans =
'32455681'
7 Comments
Steven Lord
on 25 May 2023
format longg
x = randi([intmin('uint32') intmax('uint32')], 1)
y = typecast(x, 'uint8')
format hex
x
y
swapbytes(x)
More Answers (0)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!