How Can I do image extraction of chosen region?

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I have an mammogram image . I use roipoly command to draw tumor suspicious area . Maybe something easier ways to draw that blue polygon.
My question is I need to extract that blue polygon tumor suspicious region from original image and then I will segment that extracted image.
How Can I do that ?
(The image was taken from mias database).

Accepted Answer

Image Analyst
Image Analyst on 29 Dec 2020
Once you have the mask, do this:
% Mask the image using bsxfun() function to multiply the mask by each channel individually.
% Works for gray scale as well as RGB Color images.
maskedImage = bsxfun(@times, rgbImage, cast(mask, 'like', rgbImage));
changing the names to whatever you want to call them.
  12 Comments
Image Analyst
Image Analyst on 5 Jan 2021
I already told you:
mask = false(rows, columns);
drawAnother = true;
while drawAnother
thisMask = roipoly(); % or however you want to get it.
mask = mask | thisMask;
% ask user if they want to draw another with questdlg().
promptMessage = sprintf('Do you want to Continue processing,\nor Quit processing?');
titleBarCaption = 'Continue?';
buttonText = questdlg(promptMessage, titleBarCaption, 'Continue', 'Quit', 'Continue');
if contains(buttonText, 'Quit', 'IgnoreCase', true)
drawAnother = false;
end
end
Now mask will have several polygon regions on it and you can just pass it to regionprops():
props = regionprops(mask, 'All'); % Or whatever measurements you want.
Ali Zulfikaroglu
Ali Zulfikaroglu on 6 Jan 2021
Thank you really image analyst . I added your function bsxfun and got the result which I want.

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More Answers (1)

KALYAN ACHARJYA
KALYAN ACHARJYA on 29 Dec 2020
Edited: KALYAN ACHARJYA on 29 Dec 2020
Steps:
  • Draw
  • Right Click (Cursor above the Drawing)
  • Create Mask
  • Save the Mask
  3 Comments
KALYAN ACHARJYA
KALYAN ACHARJYA on 30 Dec 2020
Edited: KALYAN ACHARJYA on 30 Dec 2020
After these steps, please follow Image Anayst answer (Below)
Ali Zulfikaroglu
Ali Zulfikaroglu on 30 Dec 2020
Thank for your suggestion also, image analyst answer works

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