finding nearest distance of a distinct value

1 view (last 30 days)
Hi, suppose I have a matrix as follows:
I =
1 1 5 1 1 1 8
1 1 1 1 1 1 1
1 1 1 1 1 1 1
1 1 5 2 1 1 1
1 1 1 1 1 5 1
1 1 1 1 1 1 1
I(3,4) is 1 . I need to know the distance and position of nearest 5 of this matrix from this 1. How to do this easily?Thanks in advance.

Accepted Answer

Andrei Bobrov
Andrei Bobrov on 18 May 2011
EDIT
[Hi Hj] = find(I~=1);
d = [Hi Hj I(I~=1) sqrt(sum(bsxfun(@minus,[Hi Hj],[3 4]).^2,2))];
ds = sortrows(d,4);
d5 = ds(ds(:,3)==5,:);
out = d5(1,:)
more
[Hi Hj] = find(I==5);
d = [Hi Hj sqrt(sum(bsxfun(@minus,[Hi Hj],[3 4]).^2,2))];
[~,jj] = min(d(:,3));
out = d(jj,:)

More Answers (0)

Categories

Find more on Statistics and Machine Learning Toolbox in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!