Funky Division Output and Mismatched Arrays

Hey, guys! i've been trying to solve this problem for the last few days and it's been driving me crazy. I had posted a few days ago and "Iain" was kind enough to offer advice but i still couldn't get the program to run properly. With some problems fixed, now i can't seem to get a normal answer.

All it has to do is divide the input of "units" and the corresponding "Values". "Values" is linked to the array "accepted" so that A = 1, B = 2, C = 3. so when I choose "A" and 3 units, I should get 0.33333 total A, but instead I get 0.0612

I feel that the problem lies in "index = find(strcmpi(elmnt,Accepted));" and "disp([(units) / Values {index} ])" I don't think it's properly matching the arrays

what obvious thing am i missing? thanks!

   Accepted = {'A','B', 'C'};
Values   = {'1','2','3'} ;
index = find(strcmpi(elmnt,Accepted));

 elmnt = input('what letter? ','s'); 
 if any(strcmpi(elmnt,Accepted))
     disp (' \n')
 else
    disp ('that''s not going to work')
 end
  units = input ('how many units of it?');

disp([((units) / Values {index} )])

disp('units of')
disp(elmnt )

[Iain]

 Accepted = {'A','B', 'C'};
 Values   = [1 2 3] ;
 elmnt = input('what letter? ','s'); 
 index = find(strcmpi(elmnt,Accepted)); 
 Value = Values(index);
 if index           %a sneaky shorthand
     disp (' \n')
 else
    disp ('that''s not going to work')
 end
  units = input ('how many units of it?');
 disp([ num2str(units/Value) ' units of ' elmnt])

Answer 1

[Walter Roberson]

Values   = {'1','2','3'} ;

defines Values in terms of character. You are not dividing by 3, you are dividing by '3'

>> '3'+0

ans =

      51

>> char(51)

ans =

3

>> 51/3

ans =

      17

>> 51/'3'

ans =

       1

[kenny]

oh yeah. thanks!