How to open file array with fopen?
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Hi, I have a list of files that look like this:
J={'File1', 'File2', 'File3'}
It is not possible to open the file using fopen this way:
 for i=1:length(J)
   fid=fopen('J(1)', 'r')
   %Some algorithms here...
   fclose(fid)
 end
Is there any possible way to use fopen by using looping? It seems like it only accepts the actual file name. Please help. Thanks!
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Accepted Answer
  Jonathan Sullivan
      
 on 1 Jul 2013
        You just need to index into J properly. J looks to be a cell array so you need to use curly brackets.
Try replacing your fopen line with this
fid = fopen(J{i},'r');
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