using forecast in combination with nlarx gives an error
1 view (last 30 days)
Show older comments
Leon
on 22 Apr 2021
Answered: Stefanie Schwarz
on 27 Apr 2021
When I try to use the forecast function in combination with a nlarx I get the following error: Unable to use a value of type idnlarx as an index
When I train the model and use the compare function everything works fine with no error message.
I am using the following code:
z = iddata(y_output, x_input, 1);
sys1 = nlarx(z(1:300),[15 15 1]);
forecast = 6;
figure(); compare(z(1:800), sys1, forecast);
Y_Pred = forecast(sys1, z(1:500), 6, z.u(501:506));
%forecast(sys,past_data,K,future_inputs);
Can anyone help?
Thx in advance. Best regards
0 Comments
Accepted Answer
Stefanie Schwarz
on 27 Apr 2021
The error message is caused by the variable "forecast=6" in your code that shadows the "forecast" function. Please rename the variable to something else.
For more info, see also:
0 Comments
More Answers (0)
See Also
Categories
Find more on Nonlinear Model Identification in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!