extract without change my NaN value

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Nurul Ain Basirah Zakaria
Nurul Ain Basirah Zakaria on 23 Apr 2021
Commented: DGM on 4 May 2021
Hi, I have a data of 420x32x20 (precip over timexlatxlon)
And then, I need to apply this formula into each grid:
%F=n/N×100
%F = drought frequency (%)
%n = number of drought months
%N= total number of months
Example:
Over the 420 months, in one grid, i need to find the how many month with drought value (-1 till -4) and then divide by all month which is 420, then multiple by 100.
%Find the drought value
for i=1:32
for j=1:20
SPI3_SM(:,i,j) = nnz(CHIRPS_SPI3_SM(:,i,j)<-1 & CHIRPS_SPI3_SM(:,i,j)>-3);
end
end
%The amount of drought value divide by period/months
for i=1:32
for j=1:20
Freq(:,i,j)=SPI3_SM(:,i,j)/420;
end
end
%Multi by 100 to ge the percent
for i=1:32
for j=1:20
New_freq(:,i,j)=Freq(:,i,j)*100;
end
end
But, when I use NNZ, it also change my NaN into zero. Is there any other way for me to do?

Answers (2)

DGM
DGM on 23 Apr 2021
Edited: DGM on 23 Apr 2021
Consider:
nanmask=isnan(myarray); % keep track of nans
outputarray=functionthatdoesthings(myarray); % do a thing
outputarray(nanmask)=NaN; % restore nans
Also, these loops are unnecessary. This thing
%The amount of drought value divide by period/months
for i=1:32
for j=1:20
Freq(:,i,j)=SPI3_SM(:,i,j)/420;
end
end
%Multi by 100 to ge the percent
for i=1:32
for j=1:20
New_freq(:,i,j)=Freq(:,i,j)*100;
end
end
is the same as just
Freq=SPI3_SM/420;
New_freq=Freq*100;
  2 Comments
Nurul Ain Basirah Zakaria
>> load('CHIRPS_SPI3_MSIA.mat')
>> nanmask=isnan(CHIRPS_SPI3_MSIA);
>> outputarray=nnz(CHIRPS_SPI3_MSIA <-1 & CHIRPS_SPI3_MSIA >-3);
>> for i=1:40
for j=1:80
SPI3_MSIA(:,i,j) = nnz(CHIRPS_SPI3_MSIA(:,i,j)<-1 & CHIRPS_SPI3_MSIA(:,i,j)>-3);
end
end
>> SPI3_MSIA(nanmask)=NaN;
Attempt to grow array along ambiguous dimension.
It comes out like this sir.
DGM
DGM on 4 May 2021
The result from this:
nnz(CHIRPS_SPI3_MSIA(:,i,j)<-1 & CHIRPS_SPI3_MSIA(:,i,j)>-3);
is a scalar. You seem to be expecting it to be a vector, given the addressing on the LHS. The result is a 2D array, but you're making a 3D mask. If you want to apply the mask to the output, you'll have to figure out its significance conceptually and figure out how to deal with the excess information. Maybe you want to do
nanmask=squeeze(any(isnan(CHIRPS_SPI3_MSIA),1));
maybe you want
nanmask=squeeze(all(isnan(CHIRPS_SPI3_MSIA),1));
I don't know.

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Jan
Jan on 23 Apr 2021
Let's simplify the code at first:
for i=1:32
for j=1:20
SPI3_SM(:,i,j) = nnz(CHIRPS_SPI3_SM(:,i,j)<-1 & CHIRPS_SPI3_SM(:,i,j)>-3);
end
end
Freq = SPI3_SM / 420;
New_freq = Freq * 100;
As far as I understand, the first loops are not useful also. Do you define SPI3_SM before the loop? What about:
SPI3_SM = sum(-3 < CHIRPS_SPI3_SM & CHIRPS_SPI3_SM < -1, 1);
What does this mean now: "it also change my NaN into zero"? Of course NaN is not in the range [-3, -1]. So what do you want to happen with NaNs?
Maybe:
SPI3_SM(any(isnan(CHIRPS_SPI3_SM), 1)) = NaN;

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