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Counting distinct elements in a vector?

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ok lets say i have a vector A = (1 1 2 2 3 4 4 4 4 5 7 7 7) the original A vector was related to actual time, hence why its increasing....i've already used the ceil function to bucket the original elements into distinct minutes... now i want to count up the elements that occur in distinct minutes.. so, for the example above- I expect a final result of 6....i cant figure out how to come up with that code.. please help

Accepted Answer

Matt J
Matt J on 8 May 2021
Edited: Matt J on 8 May 2021
numel(unique(A))
or
max(findgroups(A))
  4 Comments
James Baker
James Baker on 9 May 2021
matt,
hopefully, you don't mind a follow up question? given my A vector above in the oroginal question, what woule by the syntax to create a 2nd vector? this 2nd vector would have the values in it as follows B = (2 2 1 4 5 3). this represents the count of each unique value in the original A vector such as 2 1's, 2's, 1 3, 4 4's, 1 5 and 3 7's.and so on
James Baker
James Baker on 9 May 2021
whoops he B vector should be (2 2 1 4 1 3)... not (2 2 1 4 5 3)... doh!

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