Find max, min and create array C

A = [-2 2 3 1 6 4;4 1 0 1 0 -2];
1. Find the maximum and minimum values in the last column
- Should use size() function but how find values in last column?
2. Create a 1X2 array C consisting of all elements in the first row and the last two columns of A.

[Matt Kindig]

Hint: the last row/column of a matrix can be referenced using the 'end' keyword, i.e.,

A(:,end)  <-- last column of A
A(end,:)  <-- last row of A
A(end,end) <-- last row, last column element of A

[James Tursa]

What have you done so far?

[Matt Kindig]

By the way, as A is 2x6, "all elements in the first and last two columns of A" is a total of 6 elements, and thus cannot fit into a "1X2 array C".

[Image Analyst]

Unless it was a 1x2 cell array, but I doubt they'd have that for such an elementary homework problem.

[Kondiik]

I thought same thing how can you create array 1x2 when there is 10 elements?

[Jan]

@Kondolik: The Getting Started chapters of the documentation explain the methods for indexing clearly and exhaustively. The forum is not the reight place to ask such very fundamental basics.

You are asked to extract the 2 elements from the first row and the last two columns. Therefore I do not see any problem when A has 10 elements.

Answer 1

[Youssef Khmou]

you can start by creating a temporary variable B=A(:,end), next you can use max(B) and min(B) or you can use the function B=sort(B,'ascend') in ascending order , next the min is B(1) and the maximum is B(end)