new array using average row of the old array
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I have an array M(1000,1000) and i want to build a new array N(1000,1000), where each element of N has the old value minus the average of its row (in M). If the element is zero no action will be taken. Also, from the average the zeros should be excluded.
Can you help me?
thank you in advance
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Accepted Answer
Azzi Abdelmalek
on 13 Oct 2013
Edited: Azzi Abdelmalek
on 13 Oct 2013
Edit
out=bsxfun(@minus,M,mean(M,2)).*not(~M)
%or
idx=M==0;
out=bsxfun(@minus,M,mean(M,2));
out(idx)=0
6 Comments
Azzi Abdelmalek
on 13 Oct 2013
Edited: Azzi Abdelmalek
on 13 Oct 2013
Ok try this
idx=M==0;
moyenne=sum(M,2)./sum(not(~M),2)
out=bsxfun(@minus,M,moyenne)
out(idx)=0
More Answers (1)
Andrei Bobrov
on 13 Oct 2013
ii = M == 0;
out = bsxfun(@minus,M,sum(M,2)./sum(~ii,2));
out(ii) = 0;
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