The problem should be called "Kelvin to Celsius" as you are outputting the temperature in Celsius
Good point. Fixed this.
Why is this called "Celsius to Kelvin" rather than "Kelvin to Celsius"? The test case is the latter, not the former.
rounding problem??? O_o
Remove the vowels
Given area find sides
02 - Vector Variables 3
Find out value of sine given by degree.
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