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关于sym的一个简单问题。
就是因为没有直接定义过y(t)所以才需要每次用sym，如果写法是： syms t y(t) 那么后续可以直接使用： z0=diff(y)+a*y; 注意这里的y的类型是symfun，而不是sym 另外，版本太老的话是不支持这种用法的
3 years ago | 0
| accepted
