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Lily


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why mod(rref(A), 2) does not give the correct result?
Lets say I have the followings all in mod 2 a = [1 1 0 0 0]' b = [1 0 1 0 1]' c = [0 1 1 0 1]' clearly, c = a + b in mod 2 ...

5 months ago | 1 answer | 0

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