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Question
Integration using quad(@myfun,a,b)
I have the following function function AW1= AW_int() ASqr=aSqrSum(); BSqr=bSqrSum(); C=CSum(); delta...
10 years ago | 1 answer | 0
1
answerQuestion
Why am I getting this error? The integrand function must return an output vector of the same length as the input vector.
Hi I have the following function function AW1= AW_int(x,N) N=[10 100 1000 10000 100000]; x=[0.9 0.99 0.999 ...
10 years ago | 1 answer | 0
1
answerQuestion
Plotting a matrix of data in a graph
Hi I have outputted a <5x7> workspace variable of data using the following values of x and n: x=[0.9 0.99 0.999 0....
10 years ago | 1 answer | 0
1
answerQuestion
integrad function not returning an output vector of the same length as the input vector
I have the following function function x = rZSum(y, z) y = load('delta.txt'); z = load('aSqr.txt'); x =...
10 years ago | 0 answers | 0
0
answersQuestion
Numerical integration using a quad function
I have created the following function function x = rZSum(y, z) y= load('delta.txt'); z = load('aSqr.txt'); ...
10 years ago | 0 answers | 0
0
answersQuestion
Creating a function used loaded text files
I have the following code: function x = rZ(delta, aSqr) load(delta); load(aSqr); x = delta./aSqr; e...
10 years ago | 1 answer | 0
1
answerQuestion
Integration of a function
Hi I want to solve the integral of (delta/A^2) between 0 and 0.9999999. delta and A^2 are <5x7 double> workspace variable...
10 years ago | 0 answers | 0
0
answersQuestion
keeping precision when writing to excel
Hi I have the following script load ASqr.txt load BSqr.txt load C.txt load delta.txt realZeros ...
10 years ago | 1 answer | 0
1
answerQuestion
Integration using a loaded file
Hi I want to solve the integration of (delta/A^2) between 0 and 0.9999999. Delta and A^2 are arrays I have saved as txt fi...
10 years ago | 0 answers | 0
0
answersQuestion
How can I create a for loop inside another for loop for a geometric series?
I have the following code so far: %alphaSum.m % % %Amy Wallace, 19/02/2014 %Variable dictionary ...
10 years ago | 1 answer | 0