euclidean distance,output

we compute the euclidean distance for each received word as follows:

• 010 ---> 0.154
• 011 ---> 0.256
• 100 ---> 0.472
• 111 ---> 0.023
• 000 ---> 0.882

in the above list, the minimum distance is 0.023 corresponding to code word 111.

How to get 111(code word with minimum euclidean distance) out from the list as our output in the command window??

Answer 1

[Sean de Wolski]

I have no idea how the above is organized but if it's just an nx2 array:

C = [010 0.154
  011 .256
  100 0.472
  111 .023
  000 0.882];
[idx,idx] = max(C(:,1));
C(idx,2)

So:

[idx, idx] = max(array1);
array2(idx)

?

[mahaveer hanuman]

both are of different array and each array conssit of 90 rows .So,from that i need only co oresponding least value in above case my output should be 111.

Answer 2

[Matt Fig]

You could make a little function:

function y = mydist(x)
% Takes a three digit binary string argument.
switch x
    case '010' 
        y = 0.154;
    case '011'
        y = 0.256;
    case '100'
        y = 0.472;
    case '111'
        y = 0.023;
    case '000'
        y = 0.882;
    otherwise
        y = [];
end

Then when you want to use it:

>> y = mydist('111')

y =

      0.0230
  >>

[mahaveer hanuman]

010 ---> 0.154

011 ---> 0.256

100 ---> 0.472

111 ---> 0.023

000 ---> 0.882

i have upto 90 arrays so i can't use switch case for all

so only the respect least cooresponding value i need .in above case only output = 111

[Matt Fig]

If you only need one output, then get rid of the SWITCH, and just use an IF statement to check if the input is a match.

if strcmp(x,'111')

y = 0.023;

else

y = [];

end

[mahaveer hanuman]

lets A =[ 1 1 0 after dng some steps i got z=[ 0.2345

1 0 1 1.456

0 0 1 0.0673

. . . .....

. . . ......

. . . .....

1 1 0] 6.987]

both A and Z have 90 rows in each .now for least value of Z i need to take co-responding value as my out put so can u help me.

from above my out is

0 0 1.