Simple function and a small if problem, please try to help me
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Hello Experts,
I have the following function where the user chooses the section and with the given parameters gets a graph.
What I can't understand is why the function doesn't enter to section 2 while section 1 works perfectly?
Here is the code:
function Q1(rho,K1,K2,section)
% SDE's of 2 shares:
% dS1 = S1*(r1dt + s1dW1) ; dS2 = S2*(r2dt + s2dW2)
% Check if rho is a column vector if not, transpose it:
if size(rho,2) > 1
rho = transpose(rho);
end
% Given parameters:
r1 = 0.0001;
r2 = 0.0001;
s1 = 0.0001;
s2 = 0.0002;
% Number of simulations:
M = 100000;
% End of period is set to be t = 100 days
t = 100;
% Initial values S1(0) = S2(0) = 1:
S1_0 = 1;
S2_0 = 1;
% Generating independent normally distributed vectors, here
% concentrated at the end of the period where t = 100.
W2 = sqrt(t)*randn(M,1);
V = sqrt(t)*randn(M,1);
if section == 1
ReasonablePrice = zeros(length(rho),1);
PayoffStd = zeros(length(rho),1);
PayoffError = zeros(length(rho),1);
elseif section == 2
ProfitMean = zeros(length(rho),1);
ProfitStd = zeros(length(rho),1);
ProfitError = zeros(length(rho),1);
end
for j = 1:length(rho)
% Making W1 and W2 dependent while W and V are independent,
% cov(W1,W2) = rho(j)*Var(W2) + 0 = rho^2(j)*t.
W1 = rho(j)*W2 + V;
S1 = S1_0*exp((r1 - 0.5*s1^2)*t + s1*W1(:,1));
S2 = S2_0*exp((r2 - 0.5*s2^2)*t + s2*W2(:,1));
if section == 1
% Payoff for all of M simulations using logical expression to find
% where S2 > S1:
Payoff = (S2-S1).*(S2 > S1);
% Calculating the reasonable price: E[max(S2(100) - S1(100),0)]:
ReasonablePrice(j,1) = mean(Payoff);
PayoffStd(j,1) = std(Payoff);
PayoffError(j,1) = PayoffStd(j,1)/sqrt(M);
elseif section == 2
Profit = max(S1 - K1,S2 - K2).*(S1 > K1).*(S1 - K2);
ProfitMean(j) = mean(Profit);
ProfitStd(j) = std(Profit);
ProfitError(j) = ProfitStd(j)/sqrt(M);
end
end
if section == 1
figure(1);
plot(rho,ReasonablePrice);
xlabel('rho');
ylabel('Price');
elseif section == 2
ProfitMean = rho;
plot(rho,ProfitMean);
xlabel('rho');
ylabel('ProfitMean');
end
Accepted Answer
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