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aman
aman on 13 Mar 2014
Commented: Image Analyst on 13 Mar 2014
hi, I have made the following program which is used for refinement in image coding. mark=zeros(1,4); out1=zeros(1,4); out=zeros(1,4); x=[1 3 7 8]; for n=3:-1:1; t=2^n; for i=1:4; if (x(i)>=t);
switch mark(i)
case 0
out1(i)=sign(x(i));
mark(i)=1;
case 1
z=dec2bin(x(i),4);
out1(i)=z(1);
mark(i)=2;
case 2
z1=dec2bin(x(i),4);
out1(i)=z1(2);
mark(i)=3;
otherwise
end
else
out1(i)=0;
end
end
end
when I run this program I get finally out1 as 0 1 48 48 . Instead I should get 0 1 0 0. Can any body tell me what is the problem with my program.
  2 Comments
John D'Errico
John D'Errico on 13 Mar 2014
Edited: John D'Errico on 13 Mar 2014
Please don't title every post of yours exactly the same "related to image processing". This is confusing and it does not help anyone else who may be able to learn from your post.
As well, please don't ask the same question twice!

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Accepted Answer

Mischa Kim
Mischa Kim on 13 Mar 2014
Aman, use
out1(i) = str2num(z(1));
instead (and similar for the other out1(i) command. dec2bin outputs a string, which you need to convert back to numeric format.

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