Error in locating a reference cell for calculations
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So far I have got this code:
%%=================================================
%%to find average power first use "find" function to find the first zero in
%%Fz, have the cell referenced
%%then use nanmean for average power(av_pwr)
%%use nanmin for peak power (peak_pwr)
%%=================================================
ref= find(data{i,1}(:,5)==0);
ref=ref(1);%returns all times zero occurs then extracts first time data is 0
peak_pwr(i,1) = nanmin (data {i,1}(1:ref,5));
%preak power in coloumn E1 in all data with reference to cell found
av_pwr(i,1)=nanmean(data{i,1}(1:ref,5));
%average power in coloumn E1 in all data with reference to cell found
I have tried to locate the first zero in column E1 and then use this as a reference cell to get the peak and average power. However it is coming up with this error:
Attempted to access ref(1); index out of bounds because numel(ref)=0.
Error in code (line 53) ref=ref(1);%returns all times zero occurs then extracts first time data is 0
anyone know how to get around this?
Answers (1)
David Sanchez
on 14 May 2014
If you read the line:
Attempted to access ref(1); index out of bounds because numel(ref)=0.
you can see that
data{i,1}(:,5)==0
is never fulfilled and therefore, ref remains an empty array with no values in it.
When you tried to access its first value:
ref=ref(1)
the system complains (yields an error) because there is nor such an element. Since I do not have data, it is nor easy to tell whether any of its elements equals 0 in any moment.
5 Comments
Adrienne
on 14 May 2014
Adrienne
on 14 May 2014
David Sanchez
on 14 May 2014
the problem is in your data cell array.
In your line
ref= find(data{i,1}(:,5)==0);
who is i ? What's the type of data within data? If they are strings, ref will always be an empty array.
David Sanchez
on 14 May 2014
how are you reading the CSV file?
Adrienne
on 14 May 2014
This question is closed.
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