Plot in complex plane - Symbolic toolbox

I'm trying to plot the function of complex variable:
mu:=10;lambda:=mu;n:=100;
f2:=16*mu*n^2/(16*mu*n^2-exp(-9*lambda*(n^2-4*k^2)/(64*n^2)))
plot(f2,Re(k)=0..100,Im(k)=0..100,#3D)
and keep getting this message: Error: unexpected arguments: Re(k) = 0..100, Im(k) = 0..100 [plot::Canvas::new]
what am I doing wrong?

Answers (2)

Paulo Silva
Paulo Silva on 19 Aug 2011
That doesn't look like MATLAB code, are you using MUPAD instead?

6 Comments

My experience with MUPAD is very small, please explain what are you trying to do in the plot so I can try to help you.
I plotted something like this plot(f2,Re(f2),Im(f2),#3D) but doesn't seem to be what you want.
I managed to crash my MUPAD but what you are looking for might be this plot(f2,Re(f2),Im(f2),k=0..100,#3D) , again my MUPAD experience is very small.
A contour plot in complex plane, with singularities, something like this:
http://www.wolframalpha.com/input/?i=plot(1%2F(z*(z^2%2B1)*Log(z))
I tried plot(Im(f2),k=0..100,#3D) and plot(Im(f2),k=I*0..I*100,#3D) instead but is definitely not what I'm having in mind
sorry but I have no idea how to do it but someone else might, good luck

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mu:=10;lambda:=mu;n:=100;
f2:=16*mu*n^2/(16*mu*n^2-exp(-9*lambda*(n^2-4*(k+j*I)^2)/(64*n^2)));
plotfunc3d(f2,k=0..100,j=0..100);

5 Comments

this looks a bit better. Is there any way to see a contour plot, since I'm primarily interested in poles. I tried plot::Implicit2d, but didn't get any output.
You probably need to specify the Contours attribute for Implicit2d . See http://www.mathworks.com/help/toolbox/mupad/plot/ATTRIBUTES_Contours.html
I don't think so. What I need are poles/singularities in the complex plane, something I can't 'specify' - see my link to Wolfram Alpha above.
Any particular reason not to specify the contour levels as (say) -1e10 -1e9 -1e8 -1e7 ... 1e7 1e8 1e9 1e10 ?
Having it choose automatic contour levels might be more difficult.
I do not have the Symbolic Toolbox and have not used MuPad graphics myself, so I do not know the standard idioms.
OK, how do you plot complex functions then?

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Asked:

on 18 Aug 2011

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