Search through Cell

7 views (last 30 days)
Charles
Charles on 19 Aug 2011
Hi, I have problem working with cells.
I have a 1 x 4 cell with each cell containing an N X 1 column vector. How do I search through all the first three cell elements for the rows having a given value.
To illustrate further, if I a matrix, A = N X 4; and want to find where the values 0 occur, I do
[row column] = find(A(:,1:3) == 0);
So, essentially what I am looking for is its equivalent command for a cell.

Accepted Answer

Jan
Jan on 19 Aug 2011
What about a trivial FOR loop:
C = {rand(100, 1), rand(100, 1), rand(100, 1), rand(100, 1)};
value = 0.5;
row = cell(1, 3);
column = cell(1, 3);
for i = 1:3
[row{i}, column{i}] = find(C{1} == value);
end
This can be done by CELLFUN also, but I do not see an advantage.
Or you can create the numerical matrix explicitely and use logical indexing:
Match = find(cat(2, C{1:3}) == value);
Usually using the columns of the logical matrix Match is faster than using separate index vectors.
  1 Comment
Charles
Charles on 19 Aug 2011
Hi, thanks for your response. A loop would be too expensive as there I have more than 20 million rows. What I did initially was to create a matrix from the cell and then search using the method that I described before, but I did not want to create extra variables. Anyway, I think your last suggestion will do it.

Sign in to comment.

More Answers (1)

Daniel Shub
Daniel Shub on 19 Aug 2011
A = cell2mat(A);
[row column] = find(A(:,1:3) == 0);
A = mat2cell(x, N, [1, 1, 1, 1]);

Categories

Find more on Matrices and Arrays in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!