I wanna solve to solve

my solve equation like this....

[R2,x]=solve('((1-R2)/(1-R1)*-(b/c*R2))*x^2+(1-R2)/(1-R1)-b/c=0','((2-R1-R2)/(1-R1))*a*x^2+(b+c)*(1-R2)*x+a*(((1-R2)/(1-R1)+R1)+R2)=0','R2,x');

it is very complex i think.

so replace number(by input) from coefficient(R1,a,b,c) before!! executing solve equation.(Don't say that first solve second subs)

To my purpose, chane my code

a=input('a:');
b=input('b:'); 
c=input('c:'); 
R1=input('R1'); 
fn1=((1-R2)/(1-R1)*R1-(b/c*R2))*x^2+(1-R2)/(1-R1)-b/c; 
fn2=((2-R1-R2)/(1-R1))*a*x^2+(b+c)*(1-R2)*x+a*(((1-R2)/(1-R1)+R1)+R2); 
[R2,x]=solve('fn1=0','fn2=0','R2,x')

but it doesn't work!! help me!!!

Answer 1

[Ayush]

Hi @Yunho Choi

To solve your equations with numerical coefficients in MATLAB, you need to substitute the values into the equations before using the solve function.

This is how you can do it:

% substitute the values
a = input('a: '); 
b = input('b: '); 
c = input('c: '); 
R1 = input('R1: ');

% Define symbolic variables
syms R2 x;

% Define the equations with substituted numerical values
fn1 = ((1-R2)/(1-R1)*R1 - (b/c)*R2)*x^2 + (1-R2)/(1-R1) - b/c;
fn2 = ((2-R1-R2)/(1-R1))*a*x^2 + (b+c)*(1-R2)*x + a*(((1-R2)/(1-R1) + R1) + R2);

% Solve
solutions = solve(fn1 == 0, fn2 == 0, R2, x);

Answer 2

[Walter Roberson]

The fundamental problem here is that when you use the old form of solve that used quoted expressions, that variables defined in previous expressions do not have their values substituted when evaluating quoted expressions.

To use quoted expressions, you would have had to use

eqn1 = subs('fn1=0');
eqn2 = subs('fn2=0');
[R2,x] = solve(eqn1, eqn2,'R2', 'x')