How to colormap a 3D trajectory using a 4th array
1 view (last 30 days)
Show older comments
Hello Im having some difficulties making a 3D plot, specifically w.r.t. the colormaps
I want to plot a trajectory in 3D using arrays x,y and z. I have a fourth array (a) corresponding to the acceleration at (x,y,z), it has values between [0,1]. I want the trajectory colored using the colormap('jet') based on the acceleration array.
How do I do this
0 Comments
Answers (1)
Ashish Gudla
on 4 Aug 2014
You can use “scatter3” function to plot your trajectory and also pass the additional arguments, the size of the point and the color of the point (which in your case is the acceleration vector). "scatter3" automatically normalizes the 5th input argument values to the current colormap and uses it.
Example:
>> t = 0:0.1:10;
>> x = 5*cos(t);
>> y = 5*sin(t);
>> z = sin(t)+cos(t)+t; % A random trajectory
>> a = rand(1,101) %acceleration values generated randomly for example
>> scatter3(x,y,z,5,a)
>> colormap(‘jet’) %change colormap to required the required one
See Also
Categories
Find more on Orange in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!