loop and save problem

I have a problem with a loop I made and how I want to save it: My basic code without loop is below. I want to make this in a loop because I do not always know the amount of parts. Then I would like to save this in a structure called part. one, part.two, part.three, ...

part1 = [trigger2(endpoint(1):startpoint(2))];
part2 = [trigger2(endpoint(2):startpoint(3))];
part3 = [trigger2(endpoint(3):startpoint(4))];
part4 = [trigger2(endpoint(4):length(trigger2))];
end

The loop I have made so far is below. It seems to work but off course override the data each time (I made part 22 so check if it worked, the idea would be that it would get saved as part x). I don't know how to save it the way I want to, can anybody help? probably easy but I cant seem to figure it out.

for i = 1:length(startpoint)
    if startpoint == length(startpoint) 
    part = [trigger2(endpoint(i):startpoint(i+1))];
    else
    part22 = [trigger2(endpoint(i):length(trigger2))];
    end
end

[N]

Okay I have to first say apparently my code does not work really... For more explanation since I haven't explained it good: I have a dataset, called trigger 2, where I have determined where the moments are of start and end of movement. These are the startpoints and endpoints (yes in this code is seems weird but it gets used later on as well) I would then like to split my data in different parts, look to the first code above. I'm however having problems putting this in a loop code, to make it automatically ( I do not always know the amount of parts) and i would like to save the separate parts that I made as well. if anybody can help with the code as well? Or should I put this in another question?

[Joakim Magnusson]

It would be easier to answer if you put up an example of how your data can look like before and after the loop.

[Michael Haderlein]

Did you try the two suggestions from Joakim and me? Did they do what you want? If not, please say what the outcome of our functions is and how it differs from what you expect.

Answer 1

[N]

Actually a colleague found the answer for me, it was incredibly simple, just putting it in a cell instead of a structure. Thanks anyway for allt he help here, i appreciate it immensely !!!

[Michael Haderlein]

That's what I have suggested in my answer...

Answer 2

[Joakim Magnusson]

Not sure what you are trying to do, but maybe you mean like this?

for i = 1:length(startpoint)
    if startpoint == length(startpoint) 
        part = [part trigger2(endpoint(i):startpoint(i+1))];
    else
        part22 = [part22 trigger2(endpoint(i):length(trigger2))];
    end
end

Answer 3

[Michael Haderlein]

I don't know the context of your question, but I'm pretty sure that a structure is not the best solution for that. Also, the name "startpoint" and "endpoint" is a bit counter-intuitive in this context, but maybe it makes more sense in the context of your complete program. Anyway, if you want to save parts of this trigger2 vector and the parts might be of individual size, I'd use a cell:

 trigger2=1:20;
 startpoint=[1 4 9 17];
 endpoint=[3 7 15 18];
 part=cellfun(@(l,h) trigger2(l:h),...
   num2cell(endpoint),...
   num2cell([startpoint(2:end),length(trigger2)]),...
   'uni',false);