how to create 200 random matrices using loop..
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Abhishek sadasivan
on 23 Aug 2014
Edited: Matz Johansson Bergström
on 23 Aug 2014
Hi..I want to create separate 200 random matrices of size 32*32 , and each to be multiplied with my input matrix..whether any looping is possible here ..please help ..
thank in advance
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Accepted Answer
Image Analyst
on 23 Aug 2014
Edited: Image Analyst
on 23 Aug 2014
Try this:
tic;
inputMatrix = rand(32, 32); % Whatever you want...
for k = 1 : 200
thisRandomMatrix = rand(32,32); % Create new random matrix for this iteration.
storedMatrixes{k} = inputMatrix .* thisRandomMatrix ; % Multiply them
end
toc;
msgbox('Done with loop');
2 Comments
Image Analyst
on 23 Aug 2014
Edited: Image Analyst
on 23 Aug 2014
They are separate. Each one is in its own cell. To sum up all the elements in a particular matrix you can extract it then sum it:
thisMatrix = storedMatrixes{10}; % Get matrix #10.
theSum = sum(thisMatrix(:)); % Sum of all elements of matrix #10.
You could also store them as planes/slices in a 3D matrix if you preallocate a 3D matrix for them.
More Answers (1)
Matz Johansson Bergström
on 23 Aug 2014
I have not tried it but something like this:
n=200;
tmp = rand(32,32,n);
and then to multiply each matrix
for i=1:n
in = in*tmp(:,:,i)
end
2 Comments
Matz Johansson Bergström
on 23 Aug 2014
Edited: Matz Johansson Bergström
on 23 Aug 2014
I would argue that this is possible and very simple using a 3D matrix. The data is stored in another way, that's all and very efficient, because Matlab is made for matrices. For small matrices this does not really matter, but for larger ones it might make a difference.
My suggestion stacks the matrices into a 3d matrix and you can simply pick out the matrices like you would any other data structure.
Also, to sum all the matrices, you just have to write
sums = squeeze(sum(sum(tmp)))
This gives you the sum of all the elements in each matrix as a vector. Sums(i) contains the sum of matrix i.
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