# Indirect addressing in structure

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developer on 8 Sep 2011
Hello, I have structure P that has 20 fileds now if i have to adrress the values indirectly like
x =
4
5
6
9
and i have to addrress 4th ,5th,6th and 9th of values of structure P, how can i do that

Jan on 8 Sep 2011
You can use STRUCT2CELL to convert the struct to a cell at first:
S = struct('Field1', 1, 'Field2', 2, 'Field3', 3);
C = struct2cell(S);
disp(C{1});
disp(C{3});
% A partial list of values:
x = [1, 3];
D = C(x);
##### 2 CommentsShow NoneHide None
Andrei Bobrov on 8 Sep 2011
Hi Jan! Another way
fld = fields(P)
D = cellfun(@(x)P.(x),fld(x),'un',0);
Jan on 8 Sep 2011
@Andrei: Is FIELDS documented now? Otherwise I'd suggest the older and documented FIELDNAMES.

Harry MacDowel on 8 Sep 2011
It works like this:-
P.variable = rand(20,1);
x = [4 5 6 9];
for ii=1:4
P.variable(x(ii)) = ii;
end
##### 2 CommentsShow NoneHide None
Harry MacDowel on 8 Sep 2011
ah maybe I misunderstood your question. =)
Andrei Bobrov on 8 Sep 2011
this question the continuation of this question <http://www.mathworks.com/matlabcentral/answers/15309-variable>

Wesley Ooms on 8 Sep 2011
If i understand correct, it can be done with the command
'fieldnames' it returns the names of the fields in a cell array.
p.a=1
p.b=2
p.c=3
name=fieldnames(p)
p.(name{1})