Speech recognition (Isolated words 1-9)

Question

0 votes

Hi there,

I'm an electronic student that doing speech recognition (Isolated words 1-9) system for my school project. This project is to take any speaker voice to recognize (One,Two,...,Eight,Nine) 9 words. All the word are isolated single word.

At the moment I have some coding for :

i. Saving the wav file from input (microphone)

%This program records the voice
function [norm_voice,h] = Voice_Rec(sample_freq)
option = 'n';
option_rec = 'n';
record_len = 3;         %Record time length in seconds
sample_freq = 8192;    %Sampling frequency in Hertz
sample_time = sample_freq * record_len;
'Get ready to record your voice'
name = input('Enter the file name you want to save the file with: ','s');
file_name = sprintf('%s.wav',name);
option_rec = input('Press y to record: ','s');
if option_rec=='y'
    while option=='n',
        input('Press enter when ready to record--> ');
        record = wavrecord(sample_time, sample_freq);       %Records the input through the sound card to the variable with specified sampling frequency
        input('Press enter to listen the recorded voice--> ');
        sound(record, sample_freq);
        option = input('Press y to save or n to record again: ','s');
    end    
    wavwrite(record, sample_freq, file_name);  %Save the recorded data to a file with the specified file name in .wav format
end
[voice_read,FS,NBITS]=wavread(file_name);
norm_voice = normalize(voice_read);
norm_voice = downsmpl(norm_voice, sample_freq);
le=32;
h=daubcqf(le,'min');
function vec = normalize(vec)
temp_vec = vec-mean(vec);
sum_temp_vec = sum(temp_vec.*temp_vec);
sqrt_temp_vec = sqrt(sum_temp_vec);
vec = (1/sqrt_temp_vec)*temp_vec;
function sampled = downsmpl(voice, freq)
x=freq;
y = freq/2;
z=1;
a=1;
sampled=0;
while z<freq,
    sampled(a) = sqrt(abs(voice(z)*voice(z+1)));
    a=a+1;
    z = z+2;
end
sampled = sampled';
function [h_0,h_1] = daubcqf(N,TYPE)
%    [h_0,h_1] = daubcqf(N,TYPE); 
%
%    Function computes the Daubechies' scaling and wavelet filters
%    (normalized to sqrt(2)).
%
%    Input: 
%       N    : Length of filter (must be even)
%       TYPE : Optional parameter that distinguishes the minimum phase,
%              maximum phase and mid-phase solutions ('min', 'max', or
%              'mid'). If no argument is specified, the minimum phase
%              solution is used.
%
%    Output: 
%       h_0 : Minimal phase Daubechies' scaling filter 
%       h_1 : Minimal phase Daubechies' wavelet filter 
%
%    Example:
%       N = 4;
%       TYPE = 'min';
%       [h_0,h_1] = daubcqf(N,TYPE)
%       h_0 = 0.4830 0.8365 0.2241 -0.1294
%       h_1 = 0.1294 0.2241 -0.8365 0.4830
%
if(nargin < 2),
  TYPE = 'min';
end;
if(rem(N,2) ~= 0),
  error('No Daubechies filter exists for ODD length');
end;
K = N/2;
a = 1;
p = 1;
q = 1;
h_0 = [1 1];
for j  = 1:K-1,
  a = -a * 0.25 * (j + K - 1)/j;
  h_0 = [0 h_0] + [h_0 0];
  p = [0 -p] + [p 0];
  p = [0 -p] + [p 0];
  q = [0 q 0] + a*p;
end;
q = sort(roots(q));
qt = q(1:K-1);
if TYPE=='mid',
  if rem(K,2)==1,  
    qt = q([1:4:N-2 2:4:N-2]);
  else
    qt = q([1 4:4:K-1 5:4:K-1 N-3:-4:K N-4:-4:K]);
  end;
end;
h_0 = conv(h_0,real(poly(qt)));
h_0 = sqrt(2)*h_0/sum(h_0);   %Normalize to sqrt(2);
if(TYPE=='max'),
  h_0 = fliplr(h_0);
end;
if(abs(sum(h_0 .^ 2))-1 > 1e-4) 
  error('Numerically unstable for this value of "N".');
end;
h_1 = rot90(h_0,2);
h_1(1:2:N)=-h_1(1:2:N);

ii. Perform FFT directly from input (microphone)

% An example showing how to obtain a speech signal from microphone
% and compute its Fourier Transform (FFT)
Fs = 10000;   % Sampling Frequency (Hz)
Nseconds = 5; % Length of speech signal
fprintf('say a word immediately after hitting enter: ');
input('');
% Get time-domain speech signal from microphone
y  = wavrecord(Nseconds*Fs, Fs, 'double');
% Plot time-domain signal
subplot(2,1,1);
t=(0:(Nseconds*Fs)-1)*Nseconds/(Nseconds*Fs);
plot(t,y);
xlabel('time');
% Compute FFT
x = fft(y);
% Get response until Fs/2 (for frequency from Fs/2 to Fs, response is repeated)
x = x(1:floor(Nseconds*Fs/2));
% Plot magnitude vs. frequency
subplot(2,1,2);
m = abs(x);
f = (0:length(x)-1)*(Fs/2)/length(x);
plot(f,m);
xlabel('Frequency (Hz)');
ylabel('Magnitude');

I have some sample coding about BOF and LPC but i not sure how it work since i still not fully understand the operation of them and i seem still missing out some of the library for them..

I know I still far away from the total aim I want for this project and I hope that maybe anyone can give me a hand guide me what step do I need still or mind to share me some references coding for my speech recognition.

Hope you understand my pain since our course only teaching matlab basis but not in details and I still not fully understand the process of speech recognition.

Any help or reply will be greatly appreciated!!!

Thanks in advanced!

Regards,

ckchoy

ckchoy_0123@hotmail.com