Hello, I am trying to plot the transmission coefficient vs energy for the double barrier potential, but I get an error. May I know what I have done wrong here?
Show older comments
V_0 = 0.2800; % Barrier strength in eV
hbar = 1.054571596e-34; % Reduced Planck constant
m = 5.465629128e-32; % 0.06*m_e
L = 1.00000e12; % Well width of the RTD
a = 1.00000e11; % Barrier width
x = 0.2801:0.0001:0.6000;
k = @(x) sqrt(2*m*x)/hbar;
etta = @(x) sqrt(2*m*(x-V_0))/hbar;
gamma = @(x) V_0/(x*sqrt(1-(V_0/x)));
nu = @(x) (2-(V_0/x))/(sqrt(1-(V_0/x)));
b = @(x) sin(k*L);
d = @(x) sin(2*k*L);
s = @(x) sin(etta*a);
u = @(x) sin(2*etta*a);
y = @(x) (1-gamma*b^2+nu*u^2-nu*gamma^2*d*u*s^2+4*gamma^4*b^2*s^4)^(-1);
plot(x,y), xlabel('E'), ylabel('T(E)')

Answers (1)
See the following
V_0 = 0.2800; % Barrier strength in eV
hbar = 1.054571596e-34; % Reduced Planck constant
m = 5.465629128e-32; % 0.06*m_e
L = 1.00000e12; % Well width of the RTD
a = 1.00000e11; % Barrier width
x = 0.2801:0.0001:0.6000;
k = @(x) sqrt(2*m*x)/hbar;
etta = @(x) sqrt(2*m*(x-V_0))/hbar;
gamma = @(x) V_0./(x.*sqrt(1-(V_0./x))); %%%%%% ./ and .* %%%%%%%%
nu = @(x) (2-(V_0./x))./(sqrt(1-(V_0./x))); %%%%%% ./ and .* %%%%%%%%
b = @(x) sin(k(x)*L); % k is a function of x %
d = @(x) sin(2*k(x)*L); % k is a function of x %
s = @(x) sin(etta(x)*a); % etta is a function of x %
u = @(x) sin(2*etta(x)*a); % etta is a function of x %
y = @(x) (1-gamma(x).*b(x).^2+nu(x).*u(x).^2-... % gamma, b,nu, u etc are
nu(x).*gamma(x).^2.*d(x).*u(x).*s(x).^2+... % all functions of x
4*gamma(x).^4.*b(x).^2.*s(x).^4).^(-1); % Also note ./ and .*
plot(x,y(x)), xlabel('E'), ylabel('T(E)') % y is a function of x
2 Comments
Craig Egan Allistair Tan
on 15 Oct 2021
Alan Stevens
on 15 Oct 2021
Edited: Alan Stevens
on 15 Oct 2021
I guess doublebarrier_transmission is the name of your program, but the listing above plots y(x) vs x ok.
Categories
Find more on Systems of Nonlinear Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
