How do I contain this in one "for" loop?

fprintf('Problem 2: \n')

for index = 1:1:1
    n_value=input('Please, input an n value: \n');
    n=1:1:5;
    manipulate_n=1./(2.^n);
    sum1=sum(manipulate_n);
    fprintf('There are %f n values, the sum is %f, and the difference is %f \n',length(n),sum1,1-sum1)
end

for index = 1:1:1
    n_value2=input('Please, input an n value: \n');
    n2=1:1:10;
    manipulate_n2=1./(2.^n2);
    sum2=sum(manipulate_n2);
    fprintf('There are %f n values, the sum is %f, and the difference is %f \n',length(n2),sum2,1-sum2)
end

for index = 1:1:1
    n_value3=input('Please, input an n value: \n');
    n3=1:1:40;
    manipulate_n3=1./(2.^n3);
    sum3=sum(manipulate_n3);
    fprintf('There are %f n values, the sum is %f, and the difference is %f \n',length(n3),sum3,1-sum3)
end

Answer 1

[Image Analyst]

for index = 1:1:1
    n_value=input('Please, input an n value: \n');
    n=1:1:5;
    manipulate_n=1./(2.^n);
    sum1=sum(manipulate_n);
    fprintf('There are %f n values, the sum is %f, and the difference is %f \n',length(n),sum1,1-sum1)
    n_value2=input('Please, input an n value: \n');
    n2=1:1:10;
    manipulate_n2=1./(2.^n2);
    sum2=sum(manipulate_n2);
    fprintf('There are %f n values, the sum is %f, and the difference is %f \n',length(n2),sum2,1-sum2)
    n_value3=input('Please, input an n value: \n');
    n3=1:1:40;
    manipulate_n3=1./(2.^n3);
    sum3=sum(manipulate_n3);
    fprintf('There are %f n values, the sum is %f, and the difference is %f \n',length(n3),sum3,1-sum3)
end

That was real easy since the for loops only execute one time - basically there's no looping whatsoever.