Storing index logic in new column per iteration
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For each idx variable, I want the values to be stored in a new column per iteration. Right now, each idx is being overwritten per loop iteration. I do not want the idx logic to be stored in one column with new rows; each iteration should make a new column in the idx logic field.
for j = 2:length(fieldnames(data))
for i = 1:(length(fieldnames(data))-1)
firstoutput = data.(sprintf("variables_%d", i));
secondoutput = data.(sprintf("variables_%d",j));
data.idx2 = ismember(firstoutput(:,2),secondoutput(:,2));
data.idx3 = ismember(firstoutput(:,3),secondoutput(:,3));
data.idx4 = ismember(firstoutput(:,4),secondoutput(:,4));
end
end
Answers (1)
You would need to use i and/or j, depending on how you are thinking of an "iteration" for your algorithm, as indices into your data.idx# fields. If i and/or j are large, I would also recommend pre-allocating them as a logical/boolean vector/matrix, as appropriate for your definition of iteration.
For example, it seems like you would want to store all combinations of i and j, based on your code so you might do something like this:
L = length(fieldnames(data));
data.idx2 = zeros(L-1, L-1, 'logical');
data.idx3 = data.idx2;
data.idx4 = data.idx2;
for j = 2:L
for i = 1:L-1
firstoutput = data.(sprintf("variables_%d", i));
secondoutput = data.(sprintf("variables_%d",j));
data.idx2(i,j) = ismember(firstoutput(:,2),secondoutput(:,2));
data.idx3(i,j) = ismember(firstoutput(:,3),secondoutput(:,3));
data.idx4(i,j) = ismember(firstoutput(:,4),secondoutput(:,4));
end
end
7 Comments
Annette Ciecierega
on 2 Nov 2021
Timothy
on 2 Nov 2021
On which line do you get this error?
Annette Ciecierega
on 2 Nov 2021
Ah, OK, I see what I missed now that I'm looking at it again. The output of is member is different than what I was initially thinking. You just need another dimension on your data.idx# fields to accomodate the output of ismember. Is the length of data.variables_## fixed or variable? If it is fixed, you can add the third dimension size to the zeros call to pre-allocate your data.idx# fields. If it is variable, then you may want to make your data.idx# fields into any array of cells instead.
For cell arrays:
Preallocate using ... = cell(L-1);
Access using {} instead of () for data.idx#, like data.idx3{i,j} = ...
Annette Ciecierega
on 3 Nov 2021
Timothy
on 3 Nov 2021
You're welcome, were you able to get something working the way you wanted?
Annette Ciecierega
on 3 Nov 2021
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