select the correct row in a table with a different index in the for loop

Good mornin,

within a for loop (with an index i ranging from 1 to 1440 with an interval of 5( for i:1:5:1440)) I need to select the correct row of a table (containing 288 rows). The problem is that the index of the for loop does not correspond to the correct row of the table, because for i=5 I have to select row 2 of the table, then for i=10 I have to select row 3 of the table and so on. What can I do?

Thanks

Answer 1

[HWIK]

Is this what you are looking for?

for i=1:5:1440
    j = i==1:5:1440;
end

Where j would be your new index in sequential order.

[g]

yes, perfect now it works. thanks!

Answer 2

[dpb]

j=1;
for i=1:5:1440
  j=j+1;
  ...
end

Answer 3

[Peter Perkins]

Giulia, you got an asnwer to your specific question, but it's quite possible that you asked too specific a question, and didn't give enough context. Maybe you don't need to loop at all, consider something like

A2 = A(1:5:1440)

Also, 1440 suggests that you should be using a timetable, so maybe something like

a = tt.A(1:5:1440)

And if you need something every 5 minutes, then perhaps look into using retime.