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why does my program terminate

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Pat
Pat on 16 Sep 2011
Closed: MATLAB Answer Bot on 20 Aug 2021
Hiwhile i run this program my programhangs on ,dont now why,can anyone help me please
Fuzzification
[nu da]=xlsread('lymphoma dataset.xls')
cl=xlsread('class.xls');
for i=1:size(da,1)
for j=2:size(da,2)
if(j<size(da,2))
% x=str2num(da{i,j});
% if(isempty(x))
% x=0;
% end
else
c=unique(da(:,end));
% for i1=1:length(c)
% if(strcmp(c{i1},da{i,j}))
% x=i1;
% end
% end
% end
data(i,j-1)=x;
end
end
data1=data;
% data=data(1:300,:);
% cl=cl(1:150,:);
% data=nu;
disp('Dataset')
disp(data)
data=knnimpute(da)
[in claq]=kmeans(data,4);
for i=1:size(da,2)
d=data(:,i);
Emin=min(d);
Emax=max(d);
d1=sort(d,'ascend');
s=size(d,1)/3;
pj1=d(1:s,:);
pj2=d(s+1:end,:);
cl=in;
cla1=cl(1:s,:);
cla2=cl(s+1:end,:);
nc=10;
de=1;
k1 = mat2cell(pj1, nc*ones(1, (s/nc)),1);
k2 = mat2cell(pj2, nc*ones(1, (size(pj2,1)/nc)),1);
Rk1=(2*1)/length(pj1);
Rk2=(2*2)/length(pj2);
%class
figure('visible','off')
h = cdfplot(cla1);
y = get(h,'YData');
f1=length(y);
y = unique(y);
h1 = cdfplot(cla2);
y1 = get(h1,'YData');
f2=length(y1);
y1 = unique(y1);
low1=y(2);
low2=y1(2);
cf1=y(2)-y(1);
cf2=y1(2)-y1(1);
Pj1=low1+((Rk1-cf1)/f1)*de;
Pj2=low2+((Rk2-cf2)/f2)*de;
Aj1(i)=(Emin+ Pj1)/2;
Aj2(i) =(Pj1 + Pj2 )/2;
Aj3(i)= (Pj2 + Emax )/2;
end
  3 Comments
Andreas Goser
Andreas Goser on 16 Sep 2011
And also be specific about "terminate"
Jan
Jan on 18 Sep 2011
@Pat: You've asked 41 questions now. I'd expect that you've learned how to ask good questions and how to format your code. If you interested in getting answers, make your question easy to understand and to read would be a good idea.

Answers (1)

Vineeth Kartha
Vineeth Kartha on 3 May 2016
Hi,
Insert breakpoints at each xlsread command and see if it is one of the xlsread that is causing the problem.
Regards Vineeth
  1 Comment
Jan
Jan on 3 May 2016
@Vineeth Kartha: Did you see that the question is 5.5 years old and that the OP did not reply to questions for clarifications? I assume he was not interested in a solution.

This question is closed.

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