File returns a vector of length 29, but the length of initial conditions vector is 8.

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function ans = final_project()
CI_CO2 = [0,10];
Y0 = [0.0001,0.0001,0.0001,0.0001,0.0001,0.0001,4.75,0.7];
options = odeset('RelTol', 1e-10,'AbsTol',[1e-10,1e-10,1e-10]);
[CI_CO2,VA] = ode45(@respiratory_model,CI_CO2,Y0,options);
plot(CI_CO2,VA)
function res = respiratory_model(CI_CO2,VA)
MT_CO2 = 0.221; MT_O2 = 0.221; MB_CO2 = 0.042; MB_O2 = 0.042; PB = 760;
k1 = 0.107; k2 = 0.415; k3 = 0.2; k4 = 0.05; k5 = 0.92; h = 820067507;
u = -148822662; v = 9.8949e+06; p = -2.7670e+05; q = 3.3179e+03; r = 43;
f = 0.003; s = 2.3; g = 98; W = 0.014; S = 0.024; a = 99; b = 19.6;
d = 0.0008; n = 3; m = 98; Q = 6; QB = 0.7; QBN = 1;
CB_CO2 = 55.9; CB_O2 = 0.110; CA_CO2 = 5.6; CA_O2 = 14.1; CT_CO2 = 54; CT_O2 = 0.134;
CI_O2 = 0.1967;
eq58 = MB_CO2 + QB*(k1*(PB*CA_CO2)^k2) - CB_CO2;
eq59 = MT_CO2 + (Q-QB)*(k1*(PB*CA_CO2)^k2-CT_CO2);
eq60 = QB*(CB_CO2-CT_CO2) + Q*(CT_CO2-k1*(PB*CA_CO2)^k2) + VA*(CI_CO2-CA_CO2);
eq61 = -MB_O2 + k3*QB*((1-exp(-k4*k5*PB*CA_O2))^2 - (1-exp(-k4*PB*CB_O2/S))^2);
eq62 = -MT_O2 + k3*(Q-QB)*((1-exp(-k4*k5*PB*CA_O2))^2 - (1-exp(-k4*PB*CT_O2/S))^2);
eq63 = -k3*QB*((1-exp(-k4*PB*CB_O2/S))^2 - (1-exp(-k4*PB*CT_O2/S))^2) + k3*Q*((1-exp(-k4*PB*CT_O2/S))^2 - (1-exp(-k4*k5*PB*CA_O2))^2) + VA*(CI_O2-CA_O2);
eq64 = -VA + a*(CB_CO2)^(1/k2) - b + d*(m-k5*PB*CA_O2)^n;
eq65 = -QB + W*(h*(CA_CO2)^5 + u*(CA_CO2)^4 +v*(CA_CO2)^3 + p*(CA_CO2)^2 + q*CA_CO2 + r + f*(g-1/k5*(PB*CA_O2))^8) + QBN;
res = [eq58; eq59; eq60; eq61; eq62; eq63; eq64; eq65];
end
end
Keep getting this error message and can't figure out how to fix this. When I add to my initial conditions, my vector length increases as well. Any help would be greatly appreciated. Thank you!

Accepted Answer

Walter Roberson
Walter Roberson on 27 Nov 2021
Y0 = [0.0001,0.0001,0.0001,0.0001,0.0001,0.0001,4.75,0.7];
8 boundary conditions.
function res = respiratory_model(CI_CO2,VA)
inside the function, the current boundary conditions are stored in VA. You must return a column vector that has the same number of elements that VA has -- so an 8 x 1 vector.
eq60 = QB*(CB_CO2-CT_CO2) + Q*(CT_CO2-k1*(PB*CA_CO2)^k2) + VA*(CI_CO2-CA_CO2);
that computation uses all of VA, so eq60 in itself will have at least as many elements as VA has.
eq63 = -k3*QB*((1-exp(-k4*PB*CB_O2/S))^2 - (1-exp(-k4*PB*CT_O2/S))^2) + k3*Q*((1-exp(-k4*PB*CT_O2/S))^2 - (1-exp(-k4*k5*PB*CA_O2))^2) + VA*(CI_O2-CA_O2);
Also uses all of VA
eq64 = -VA + a*(CB_CO2)^(1/k2) - b + d*(m-k5*PB*CA_O2)^n;
Also uses all of VA
res = [eq58; eq59; eq60; eq61; eq62; eq63; eq64; eq65];
Since res includes three items each of which has as many items as VA has, then the size of res will be 3 times the size of VA, plus the length of the entries that are scalars. 5 scalar entries + 3 * 8 = 29 returned elements.

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