Cycle counter with reset

4 views (last 30 days)
Luccas S.
Luccas S. on 15 Dec 2021
Commented: Sargondjani on 18 Dec 2021
I apologize for not having developed any code for this part, because I have no idea how to do it. So, I'm going to work with the block diagram and what I've created so far.
I can't think of a way to do this:
Basically, when p_fix is ​​found it is to check if PE>p_fix every 5 cycles repeatedly until IC occurs. If PE>p_fix is ​​not respected during these 5 cycles, it is to evaluate 5 cycles again and again....
What has been programmed so far:
for n = 1:size(t,1)
if n>=4
X = [Ia(n-1,1) Ia(n-2,1) ; Ia(n-2,1) Ia(n-3,1)];
future = [Ia(n,1) ; Ia(n-1,1)];
C = X\future;
Ia_future(n,1) = C(1,1)*Ia(n,1)+C(2,1)*Ia(n-1,1);
p(n,1) = (1+0.2)*max(PE);
if PE(n,1)>p(n,1)
p_fix = p(n,1);

Accepted Answer

Sargondjani on 16 Dec 2021
you can use the function mod. For example:
if mod(n,5) == 0
or variants thereof.
Luccas S.
Luccas S. on 17 Dec 2021
I think it would be interesting to work with if (mod(n,5)==0) && (PE(n,1))>p_fix)
or is it not necessary?
Sargondjani on 18 Dec 2021
Yes, think that's what you need. But my advice is to always check if an algoirthm does what you expect.

Sign in to comment.

More Answers (0)


Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!