Solution of equation of difference

Hello! So I'm trying to solve this equation:

for A>0 and being my main variable

Initial value of y(-1)=3 and for N=30 loops

This is the code I've managed to write:

function res = my_matlab_function(A,N)

%definition of y(-1)=3
y_1=3;


% calculating the first value of y(0)
y(0)=0.5*y_1+(0.5*(A^2))/(y_1);

%calculating the rest 

for i=1:N-1
    
    y(i)=0.5*(y(i-1)+((A^2)/y(i-1))); 
    
result = my_matlab_function(A,N);
disp(['A= ' num2str(A) 'Result=' num2str(result)])
   
end

but MATLAB returns to me the followed error:

Not enough input arguments.

Error in my_matlab_function (line 8)
y(0)=0.5*y_1+(0.5*(A^2))/(y_1);
 

Answer 1

[Yash Srivastava]

Hello Nick,

I am assuming that you are trying to run the script file directly by pressing the ‘Run’ button or executing the file from command window. For a file with function to run properly, you need to pass arguments.

You may refer the below documentation to pass arguments to functions with the help of ‘Run’ button:

Configure the Run Button for Functions

You may also refer the below link to pass arguments to functions using command window:

Calling a function in MATLAB

Also, Array indexing starts from 1 in MATLAB. You may adjust your index values accordingly.