how to calculate cauchy product in summation

a(1)=1;
b(1)=1;
c(1)=1;
S=0;
Z=0;
for i=1:20
    for p=1:i-1
        a(i+1)=(1/(i+1)).*(a(i)-b(i));        
        
        b(i+1)=(1/(i+1)).*(a(i)-S-b(i));
        c(i+1)=(1/(i+1))*(Z-c(i));
        S=S+a(p)*c(i-p);
        Z=Z+a(p)*b(i-p);               
        
        disp([S Z])
    end    
end

S ,Z are cauchy product how to calculate

[Ankit]

what problem you are facing ?.. inside the loop you are trying to access the element which is not defined

a(i+1)=(1/(i+1)).*(a(i)-b(i));

[shiv gaur]

I am not able to calculate the value the value od S and Z inside the loop which is dependent on the equation of a(i) b(i) and c(i) solve the problem this is new problem

Answer 1

[Jan]

The shown code cannot run. In the 1st iteration of the "for i" loop, the inner loop is not entered: "for p = 1:i-1". In the 2nd iteration i=2 the innerloop is entered and in the line

a(i+1)=(1/(i+1)).*(a(i)-b(i));
%                   ^^^  ^^^

The not existing elements a(2) and b(2) are requested.

Seeing only the failing code does not allow to suggest an improvement, because the readers have no chance to guess, what you want to do instead.

[shiv gaur]

pl see the runing program

a(1)=0;

b(1)=1;

c(1)=0;

S=0;

Z=0;

for i=1:20

for p=1:i-1

a(i+1)=(1/(i+1)).*(a(i)-b(i));

S=S+a(p)*c(i-p);

b(i+1)=(1/(i+1)).*(a(i)-S-b(i));

Z=Z+a(p)*b(i-p);

c(i+1)=(1/(i+1))*(Z-c(i));

disp(Z)

end

end

[shiv gaur]

resolve the problem

[Jan]

@shiv gaur: You have been asked repeatedly to use a proper code formatting. Please read an consider this: https://www.mathworks.com/matlabcentral/answers/help/rtc#rtc_summary . Thanks.

"pl see the runing program" - the code still stops with an error and we still cannot guess, what it should calculate.

"Resolve the problem" is not a polite way to ask for help, but a rough command. Refusing to post your code in a formatted way and posting not running code repeatedly let it look, like it is your intention to provoke the community.