PDEPE for simple coupled ODE-PDE system?
7 views (last 30 days)
Show older comments
Reposting (just once) to see if anyone has any insight. I solved the problem using the "method of lines" technique but was really curious about my original question and the interesting behavior I observed.
Hi all, I have a system of coupled reaction-diffusion ODEs and PDEs that I wish to use pdepe to solve, and have been running into unexpected outputs. To check, I used a simpler "test" system which could be solved in an exact fashion, purely to test the output of PDEPE.
It is simply:
function [cc,ff,ss]=brpde(x,t,u,dstatedx)
mu=0.02;
u1=u(1);
u2=u(2);
if (x >5)
du1 = -0.07*u1;
else
du1=0;
end
if (x > 5)
du2=-0.07*u2;
else
du2=0;
end
ss=[du1;
du2];
ff=[0;
mu*dstatedx(2);];
cc=[1;
1;];
return
I have set the boundary conditions to impose no flux and the left and right hand boundaries (this should work, I believe, even for the ODE variable u1 where flux is zero throughout the slab).
function [pa,qa,pb,qb]=brbc(xa,ua,xb,ub,t) vecone=ones(2,1); veczero=zeros(2,1); pa =veczero; qa = vecone; pb = veczero; qb = vecone; return And suitable initial conditions:
function u0=bric(x) u0=[10; 10;]; return The output for u2 looks correct as I would expect it. However, although the exact solution is that u1 (the variable with no flux) should asymptotically approach zero for x>5 and stay at 10 for x<5, at the 'interface', ie near x=5, the solutions transiently dip below zero (even when the mesh is made finer or the error tolerances are made more stringent). It's confusing behavior, and I am wondering whether it's since pdepe is not suited for mixed ODE-PDE systems. When I code this simple system into a discretized forward Euler, of course the output is as I would predict it.
Thought I would reach out to the experience of the community. Anyone have suggestions? Or is there an obvious error in the above? (My real application has coupling between the ODEs and PDEs, but if it doesn't work for this test case, I am leaning toward hard-coding it).
Thanks in advance! VI
0 Comments
Accepted Answer
Torsten
on 6 Jan 2015
I guess the behaviour stems from the discontinuity of u1 at x=5.
Try
du1 = -0.07*u1
instead of
if (x >5)
du1 = -0.07*u1;
else
du1=0;
end
in your code to see if my guess is correct.
Best wishes
Torsten.
More Answers (0)
See Also
Categories
Find more on Ordinary Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!