# How to group arrays in a cell based from data?

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Heirleking on 22 Apr 2022
Commented: Heirleking on 10 May 2022
I have this graph representing force vs. time. Then, I found its peaks to group them representing sort of a trend. I need to create two different cells, one for the forces with positive peaks and one for the negative ones, and two different cells of the location in the "x" axis (time) of the positive and negative peaks.
For example, for the negative peak forces, I was using histcounts.
pks_f_min = [ -68.0928; -63.6998; -110.9254; -103.2375; -132.8908; -125.2030; -137.2840; -113.1220; -148.2667; -144.9718; -151.5615; -159.2494; -151.5615 ]
[~,~,f_bins]=histcounts(pks_f_min, flip([0 -10 -20 -30 -40 -50 -60 -70 -80 -90 -100 -110 -120 -130 -140 -150 -160]));
u=unique(f_bins);
for k=1:numel(u)
groups_f_min{k}=pks_f_min(f_bins==u(k));
end
In the end, groups_f_min needs to look like this:
groups_f_min = { [ -68.0928; -63.6998 ] [-110.9254; -103.2375 ] [ -132.8908; -125.2030 ] [ -137.2840; -113.1220] [ -148.2667; -144.9718 ] [ -151.5615] [ -159.2494; -151.5615 ]}
Since I will be using this code for other graphs, is there a way to make it automatically?. For instance, other force patterns may need to be grouped in a cell consisting of two, three, or four arrays. For example, the array in the cell groups_f_min, which is alone (-151.5615), would be accompanied by another value
Voss on 23 Apr 2022
In that case, I guess the bins for grouping (in both the positive and negative peaks cases) should be based on the times when the load is applied.
Heirleking on 10 May 2022
Do you mind explaining what do you mean by based on times ? Displacement peaks and force peaks do not occur at the same time

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