How can I replace the value of an outlier rather than delete it?

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Hi! I have used this method to find and eliminate the outliers from a gaussian feature of my data set:
plot(Fetal_table.mean_value_of_short_term_variability) %Fetal_table is the table of all the features in the data set and table.mean_value_of_short_term_variability is the gaussian features in which I want to work on the outliers
vec_out = isoutlier(Fetal_table.mean_value_of_short_term_variability,"grubbs");
plot(Fetal_table.mean_value_of_short_term_variability, "og"); hold on;
Fetal_table(vec_out,:)=[]; %with that I'm deleting the outliers but I want to substitute them with a value of interest
  1 Comment
Mathieu NOE
Mathieu NOE on 17 May 2022
simply put the required value instead of [] (obvious answer)
it depends of course of what you mean by "value of interest" (interpolation, fixed value ,...)
is it a fixed value computed from somewhere else in your code ? if that is the case , doing the substitution is rather straigthforward
Fetal_table(vec_out,:) = new_value(s); % I want to substitute outliers with a value of interest

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Answers (1)

Nihal Reddy
Nihal Reddy on 3 Jun 2022
I understand you want to eliminate the outliers from a gaussian feature of the data set.
Fetal_table(vec_out,:) = [];
In the above line of code you can just replace the “[]” with variable “value_of_interest” like this
Fetal_table(vec_out,:) = value_of_interest;
The variable “value_of_interest” can be scalar or vector depending on your need.

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