Is it possible to use the smooth function with a multidimensional matrix having NaN values?

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The NaN values would be the points where the smooth function generates the new values.
Hope this is clear. Thank you!

Answers (1)

Sergio Yanez-Pagans
Sergio Yanez-Pagans on 23 May 2022
  1 Comment
alberto tonizzo
alberto tonizzo on 23 May 2022
Thank you but I have a matrix with 5 dimensions...
Matrix dimensions must agree.
Error in smoothn>dctn (line 704)
y = y.*w{dim}(:,ones(1,n));
Error in smoothn>@(x)dctn(x) (line 632)
z = cellfun(@(x) dctn(x),z,'UniformOutput',0);
Error in smoothn>InitialGuess (line 632)
z = cellfun(@(x) dctn(x),z,'UniformOutput',0);
Error in smoothn (line 421)
z = InitialGuess(y,IsFinite);

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