# how can I increase the size of an incremental vector filling the space with zeros

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Sarah Boukarras on 19 Jun 2022
Answered: Image Analyst on 19 Jun 2022
Hi, I have an incremental vector of lenght 5
a = [1 5 8 11 14]
I want to stretch a and create a new vector of length 14 in which all the empty positions between the values of a are replaced by zeros
b = [1 0 0 0 5 0 0 8 0 0 11 0 0 14]
I have already tried interpolation but doesn't seem to work
Any suggestion is very much appreciated

Abolfazl Chaman Motlagh on 19 Jun 2022
use ismember function.
X = cumsum(randi(3,1,5))
X = 1×5
1 3 5 7 10
Y = 1:X(end);
Y = ismember(Y,X).*Y
Y = 1×10
1 0 3 0 5 0 7 0 0 10
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Sarah Boukarras on 19 Jun 2022
Yes, that worked. Thanks a lot!!

### More Answers (1)

Image Analyst on 19 Jun 2022
The accepted answer might work but I think it's complicated and the simpler answer is to just do this:
a = [1 5 8 11 14];
b(a) = a
b = 1×14
1 0 0 0 5 0 0 8 0 0 11 0 0 14
I mean, how much simpler could it be? If you like my answer, you can vote for it.