how to solve the program?

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prajith samraj
prajith samraj on 18 Jul 2022
Edited: prajith samraj on 26 Jul 2022
Unrecognized function or variable 'e1'.
s1=x3.^2+x1*x3+x1.^2;
s2=x1.^4+x1.^3*x3+x1.^2*x3.^2 +x1.^2*x3.^2+x1*x3.^3 + x3.^4;
%s1=x2.^2+x1*x2+x1.^2;
%s2=x1.^4+x1.^3*x2+x1.^2*x2.^2 +x1.^2*x2.^3 + x2.^4;
%u1 = -e1-e2;
%u2 = beta*e1*k1 +gamma*e1*k2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
u1 = -e2-e1;
u2 = beta*e1*s1 + gamma*e1*s2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
%sys-I
dx1=x2;
dx2=-alpha*x2-omegaf*x1-beta*x1.^3- gamma*x1.^5+ff1*cos(W1*t);
%sys -II
dx3=x4+u1;
dx4=-alpha*x4-omegaf*x3-beta*x3.^3- gamma*x3.^5+ff2*cos(W2*t)+u2;
de1=dx3-dx1;
de2=dx4-dx2;
e1 = x3-x1;
e2= x4-x2;
de1=e2+u1;
de2=-alpha*e2-omegaf*e1-beta*e1*s1- gamma*e1*s2+ff2*cos(W2*t)-ff1*cos(W1*t)+u2;
dy = [dx1; dx2; dx3; dx4];
end
  2 Comments
prajith samraj
prajith samraj on 18 Jul 2022
i need e1 and e2 graph. what can i do?
Lateef Adewale Kareem
Lateef Adewale Kareem on 19 Jul 2022
e1 = y(:,3)-y(:,1);
e2= y(:,4)-y(:,2);

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Accepted Answer

Sam Chak
Sam Chak on 19 Jul 2022
Try manipulating the parameters to get different results.
% Solver
tspan = [0 20];
x10 = 0.11;
x20 = 0.1;
x30 = 0.21;
x40 = 0.2;
y0 = [x10; x20; x30; x40];
[t, y] = ode45(@(t, y) f(t, y), tspan, y0);
% Plots
e1 = y(:, 3) - y(:, 1);
e2 = y(:, 4) - y(:, 2);
subplot(2,1,1)
plot(t, e1), grid on, xlabel('t'), ylabel('e_{1}')
subplot(2,1,2)
plot(t, e2), grid on, xlabel('t'), ylabel('e_{2}')
function dy = f(t, y)
% parameters
alpha = 0.5;
omegaf = -1;
beta = 0.8790;
gamma = 0.3000;
W1 = 1.4450;
ff1 = 0.5381;
W2 = 1.4450;
ff2 = 0.5381;
% assignment
x1 = y(1);
x2 = y(2);
x3 = y(3);
x4 = y(4);
e1 = x3 - x1;
e2 = x4 - x2;
s1 = x3^2 + x1*x3 + x1^2;
s2 = x1^4 + (x1^3)*x3 + (x1^2)*(x3^2) + (x1^2)*(x3^2) + x1*(x3^3) + x3^4;
u1 = - e2 - e1;
u2 = beta*e1*s1 + gamma*e1*s2 + omegaf*e1 - ff2*cos(W2*t) + ff1*cos(W1*t);
% sys I
dx1 = x2;
dx2 = - alpha*x2 - omegaf*x1 - beta*x1^3 - gamma*x1^5 + ff1*cos(W1*t);
% sys II
dx3 = x4 + u1;
dx4 = - alpha*x4 - omegaf*x3 - beta*x3^3 - gamma*x3^5 + ff2*cos(W2*t) + u2;
de1 = dx3 - dx1;
de2 = dx4 - dx2;
dy = [dx1; dx2; dx3; dx4];
end
  2 Comments
prajith samraj
prajith samraj on 19 Jul 2022
i need the value of e1dot and e2 dot graph
Sam Chak
Sam Chak on 19 Jul 2022
@prajith samraj, I'm a little confused now. In your comment, you clearly mentioned that you need e1 and e2 graph. Perhaps, you unintentionally confused yourself with e1dot and e2dot?
Please edit the title of your question for clarity...

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