How to use regex to obtain double values?

I have an array of strings which contains some units. I have attahced the array.

   unq = ["10 lux";"10lux";"15";"15.0";"15.5 Lux";"15luX";"15lux";"20lux";"36lux";"42lux";"9lux"]

They are put in different format on different days. So, I get 11 unique entries. I used the following code only to keep the numeric part.

trimData = strtrim(unq);
regexData = regexp(trimData,'\d*','Match');
cleanedData = cell(numel(unq),1);
for kk = 1:numel(unq)
    if length(regexData{kk}) >= 1
        cleanedData{kk} = regexData{kk}(1);
    end
end
cleanedData = str2double(string(cleanedData));

I got

   cleanedData = [10;10;15;15;15;15;15;20;36;42;9]

I am not getting 15.5 in the resulting array. How do get the numbers in which the digits after decimal place is not '0'? How do I write a regular expression for that?

Answer 1

[Walter Roberson]

Extending to the possibility of fraction values that start with decimal point (with no leading zero), and extending to support negative values

But not extending to exponential format:

   unq = ["10 lux";"-10lux";"15";"15.0";"15.5 Lux";"15luX";"15lux";"20lux";"36lux";"42lux";".9lux"]

unq = 11×1 string array
    "10 lux"
    "-10lux"
    "15"
    "15.0"
    "15.5 Lux"
    "15luX"
    "15lux"
    "20lux"
    "36lux"
    "42lux"
    ".9lux"

   regexData = regexp(unq, '(-?\d+(\.\d*)?)|(-?\.\d+)', 'match', 'once')

regexData = 11×1 string array
    "10"
    "-10"
    "15"
    "15.0"
    "15.5"
    "15"
    "15"
    "20"
    "36"
    "42"
    ".9"

[Atanu]

Exactly what I needed. Thanks a lot, Walter!