Ranking of an array.

Hi, How can I do array rank of a matrix. Such that: [1,5; 7 9; 2 0] will produce [2 4; 5 6; 1 3]. I mean, all variables should be /ranked in an increment order. Lowest will be 1, the highest will be n

[bym]

how does [1,5; 7 9; 2 0] produce [2 4; 5 6; 1 3]?

I don't understand what your goal is

Answer 1

[Jan]

I assume, the result should be [2 4; 5 6; 3 1] with the last two elements swapped. The method is called sorting, not ranking.

M = [1,5; 7 9; 2 0];
[dummy, index] = sort(M(:));
R(index) = 1:numel(M);
R = reshape(R, size(M));

[Abdullah Muratoglu]

Absolutely correct.

Thanks

[Abdullah Muratoglu]

I realized, this code gives the same numbers, different ranks/sorts.

E.g: [3 3] will be ranked as [1 2] not [1 1]. How can I overcome this?

[Andrei Bobrov]

A = [6 7

7 3

4 1]

[a, ignore, c] = unique(A);

B = A;

a1 = 1:numel(a);

B(:) = a1(c)

[Abdullah Muratoglu]

perfect!

Thanks