Central part of a matrix

2 views (last 30 days)
Auryn_
Auryn_ on 24 Feb 2015
Commented: Sean de Wolski on 25 Feb 2015
Hello,
If a have a Matrix M and I want to create a new one, call it Central_M, which should be the central part of M and of a defined size s, how can I do it?
M_central = ?
Thanks in advance for your reply.
  2 Comments
Chris McComb
Chris McComb on 24 Feb 2015
What exactly do you mean by 'central'? And can you define s?
Auryn_
Auryn_ on 25 Feb 2015
Central means that I want to take only the central part of the matrix of a defined size s. s = imcrop(I,[max(1,i-10) max(1,j-10) 23 23]);

Sign in to comment.

Answers (2)

Jos (10584)
Jos (10584) on 25 Feb 2015
Something like this?
M = spiral(10) % test matrix
S = 2 % s elements around the central position
% the resulting matrix will be 2*S+1 squared in size
dx = -S:S ;
RC0 = ceil(size(M)/2) % central position
OUT = M(RC0(1)+dx, RC0(2)+dx)

RAGHAVENDRA
RAGHAVENDRA on 25 Feb 2015
Edited: Guillaume on 25 Feb 2015
M_central=M(floor(size(M,1)/2)-floor(s/2):floor(size(M,1)/2)+floor(s/2),floor(size(M,2)/2)-floor(s/2):floor(size(M,2)/2)+floor(s/2));
The above instruction will work, you can use 'round' instead of 'floor' to change the matrix indices accordingly.
  3 Comments
Auryn_
Auryn_ on 25 Feb 2015
I receive an error message :(
RAGHAVENDRA
RAGHAVENDRA on 25 Feb 2015
Edited: RAGHAVENDRA on 25 Feb 2015
It is working perfectly for me, this is the example that i have tried
M=randi(5,[10 10]);
s=2;
M_central=M(floor(size(M,1)/2)-floor(s/2):floor(size(M,1)/2)+floor(s/2),floor(size(M,2)/2)-floor(s/2):floor(size(M,2)/2)+floor(s/2))
What is the error message?

Sign in to comment.

Categories

Find more on Creating and Concatenating Matrices in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!