Don't get what is happening in matlab sin() function. need to know difference between sin(2*50*pi*t) and sin(2*1*pi*t)
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Hi,
I am using Matlab to plot the sin graph. But when I put sin(2*50*pi*t) it shows something else than the sinusoidal curve. Can you please help me to find out why it is happening? Thanks in advance.
Code:
t = 0:0.1:20;
x = sin(2*50*pi*t);
y = sin(2*1*pi*t);
subplot(2,1,1)
plot(t,x)
subplot(2,1,2)
plot(t,y)
1 Comment
Steven Lord
on 9 Sep 2022
It wouldn't help in this case but if you're computing the sine of pi times some angle, consider using the sinpi function instead of explicitly computing pi times the angle and calling sin.
Accepted Answer
Torsten
on 9 Sep 2022
t1 = 0:0.001:1;
x = sin(2*50*pi*t1);
t2 = 0:0.1:1;
y = sin(2*1*pi*t2);
subplot(2,1,1)
plot(t1,x)
subplot(2,1,2)
plot(t2,y)
3 Comments
John D'Errico
on 9 Sep 2022
Edited: John D'Errico
on 9 Sep 2022
@William Rose - I almost wish you had made your comment an answer. While @Torsten is completely correct, he has not made this important point explicit, as did you. And while I could move your comment to an answer, I'd rather let you do it, or not as you desire.
More Answers (1)
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