# Indices from Max function to Extract Data

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Rajesh Rajaram on 11 Mar 2015
Commented: Rajesh Rajaram on 11 Mar 2015
I have two arrays:
A=[1 2; 3 2; 3 4];
B=[1 2; 3 4; 5 6];
When I calculate [M,I] = max(A,[],2), I get
M =
2
3
4
I =
2
1
2
Which is fine. Now I want to report values of B for the When A=M in each row; that is:
1
4
5
Is there a way to avoid using the for loop to build my answer array (have a large data set)? I used:
[I_row, I_col] = ind2sub(size(A),I)
but that doesn't seem to help my cause. Kindly help

Andrew Newell on 11 Mar 2015
Your question gets a little garbled in the middle, and I'm not sure what you're after. If you want the values [1 4 5] from B, those correspond to the position of the minima in each row of A. Is that what you want?
Rajesh Rajaram on 11 Mar 2015
So sorry for the confusion. My bad!! I just need the values of B corresponding to the position which has the max values of A.
2 3 6 (and not what I typed. SORRY!!)
I have since found the expression B(sub2ind(size(A), 1:size(A,1), I'))' which seems to do the trick.
But if I want the dim in max function to be changed from 2 to 1, then I have to manually input for sub2ind to get my desired answer.
Is there a generic expression to get the right answer irrespective of the dim that I use in the max function?

Andrei Bobrov on 11 Mar 2015
Edited: Andrei Bobrov on 11 Mar 2015
A=[1 2; 3 2; 3 4];
B=[1 2; 3 4; 5 6];
n = 1;
[~,I]=max(A,[],n);
c ={(1:size(A,3-n))',I(:)}; % EDIT
l = n == 1;
out = B(sub2ind(size(A),c{[l,~l]+[1,1]}));

Rajesh Rajaram on 11 Mar 2015
Thank you very much for the suggestion. But the code is crashing when n is changed to 2.
Andrei Bobrov on 11 Mar 2015
fixed
Rajesh Rajaram on 11 Mar 2015
Thank you so much!!